WAEC GCE – PHYSICS
Physics

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Physics-Obj
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(1a)
Young modulus of a material or the modulus of elasticity.

(1b)
Potential Energy to kinetic Energy.

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(6a)
(i) It can cause short and long term sun burn effects.
(ii)It can cause blindness when flashed to the eyes.

(6b) Energy = hf
= 6.60×10^-34 × 4.82×10^14
= 3.18×10^-19J
= 1.99ev

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(7)
V = 2πR/T
R = 9.6×10^6 + 6.4×10^6 =16×10^6 m
T = 24hrs =(24×60×60)s
V = 2×3.142×16×10^6/24×60×60
V = 1162.96m/s

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(2)
e = 0.7m
m=60 × 10^-3kg = 6.0×10^-2kg
K = 200Nm^-1
W = 1/2ke² = 1/2mv²
1/2ke² = 1/2mv²
V² = ke²/m = 200×0.7²/6.0×10^-2
V² = 98×10²/6
V² = 16.33×10²
V = √1633
V = 40.4
Speed = 40.4ms^-1

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(3)
(i) Optical fibres have extremely high bandwidth
(ii) They have longer transmission distance
(iii) They have resistance to electromagnetic interference

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4a)
Geo stationary satellite is used to provide visible and infrared images of Earth’s surface and atmosphere.

b) Polar orbits satellites are often used for earth-mapping, earth observation, capturing the earth.

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5a)i) Centrifugal Force
ii) Gravitational pull

(5b)
Ft = mDv
where F = force
t = time
Dv = change in velocity
m = mass of object

Hence F = mDv/t
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12c) i)Metal
ii) Stone
Specific latent heat of vaporiazation is the amount of energy per kg (unit mass) required to change liquid to vapour without corresponding change in temperature

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8ai
Mass is measured in Kg
Weight is measured in Newton
Mass is a scalar quantity
Weight is a vector quantity
Mass is constant
Weight varies
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(11a)
Lenz’s law states that an induced current is in such direction that it’s magnetic effect opposes the change by which the current is induced.

(11b)
(i) Magnets are used in construction of speakers.
(ii) They are used to store data in computers.
(iii) Used in magnetic resonance imaging machines.

(11ci)
(a) Two coils: So as to produce an induced current from one coil to the other.

(b) an iron core: To increase the strength of the magnetic field.

(11cii)

(11d)
Total resistance in series
Rt = R1 + R2
= 500 + 400
Rt = 900ohms

Taking E = 6v
E = V + ir
E = VR + Ir
E = I ( R + r)
I = E/R + r
taking r = 200ohms
I = 6/900+200
I = 6/1100
I = 0.005A

Hence the voltmeter reading
V = IR
= 0.005 × 200
= 1.09v
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