Nabteb 2016 MATHEMATICS  Essay and Obj & Theory Answer Now Available -MAY/JUNE

Maths obj

1dbcbaacaac

11aaddabadac

21ccccbbdada

31bcdadabcbb

41cbadbdaabd

1a)

9^11.25*9^1.75/9^2

= 9^11.25 1.75/9^2

=9^13/9^2

=9^13-2

=9^11

1b)

i) log2 = log10/5

=log10-log5

=1-log5

=1 0.699

=0.30

ii) log15=log3*5

= log3 log5

=0.479 0.699

=1.17

2a)

1/2x + 3/4y = 1 ——– (1)

x-1/2y=-1 ————(2)

multiply equation (1) through by 4

(1/2x + 3/4y) 4 = 1*4

2x+4y=4 ————-(3)

multiply equation (2) through by 2

(x – 1/2y)2 = -1*2

2x-y=-2 ————–(4)

solve equ (3) and (4) simultaneously

2x+3y=4

2x-y=-2

0+4y =6

4y/4 = 6/4

y=1.5

subtitute y=1.5 into eqa (4) to solve for x

2x-y=-2

2x-(1.5)=-2

2x-1.5=-2

2x=-2+1.5

2x/2 = -0.5/2

x= -0.250

2b)

Volume (v) = 1/3a^2h

given that

V= 180cm^3

h= 15cm

a = ?

180 =1/3*a^2*15

180=15a^2/3

180/5=5a^2/5

a^2= 36

a = root36

a = 6cm

the lenght of the side of the base is 6cm

 

3a)

Tn= a+(n-1)d

T3= 26

T10= 26+28

T3=a +(3-1)d=26

a+2d=26———-(1)

T10=a+(10-1)d=54

a+ 9d=54———(2)

solve equa(1) and (2) simutaniously

a+2d=26

a +9d=54

-7d/7 = -28/-7

d= 4

subtitute d=4 into equa (1)

to solve for a

a+2d=26

a+2*4=26

a+8=26

a=26-8

a= 18

i)the first term (a) from above is 18

ii) the common difference (d) from above is 4..

3b)

sum of angle in a polygon

=(n-2)180

where A = 5

=(5-2)180

=3*180 = 540

the sum of polygon is 540

therefore x+x+8+2x-1+x-3

3x =540

8x=540+4

8x/x = 544/8

x= 68

 

4a)

t=1-x/1-x

t(1-x)=1+x

t-tx =1+x

-tx-x=1-t

x(-t-1)/(-t-1) = 1-t/(-t-1)

x= 1-t/-t-1

x= 1-8.5/-8.5-1

x = -7.5/-9.5 = 7.5/9.5

x= 0.79

 

5a)

(709.18)^2 – (290.82)^2

=(709.18)^2/(290.82)^2

= 502936.27/84576.27

=5.94

5b)

Isosceles (trapezium) Area = 1/2(a*b)h

=1/2*a*b*h

=1/2*8*12*12

=1/2*1152

=576cm^2

 

6a)

2x/3=6-x / 1+x

2x(1+x)=3(6-x)

2x+2x^2=18-3x

2x^2+2x+3x-18=0

2x^2+5x-18=0

2x^2-4x+9x-18=0

(2x^2 -4x)+99x-18)=0

2x(x-2)+9(x-2)=0

(x-2)(2x+9)=0

x-2=0 or 2x+9=0

x-2=0 or 2x+9=0

x=2 or 2x=-9

x=2 or x=-9/2

6b)

y=2x-1—(1)

y=2x^2 – 3x-4–(ii)

subt for y inj eqn (ii)

2x^2- 3x-4=2x-1

2x^2-3x-2x-4+1=0

2x^2-3x-2x-4+1=0

2x^2-3x-2x-4+1=0

2x^2-5x-3=0

2x^2+x-6x-3=0

(2x^2 + x)- (6x-3)=0

x(2x+1)-3(2x+1)=0

(2x+1)(x-3)=0

(2x+1)(x-3)=0

2x+1=0 or x-3=0

x= -1/2 or x=3

but y=2x-1

when x=3

y=2(3)-1

y=6-1

y=5

when x=-1/2

y=2(-1/2)

y=-1-1

y=-2

 

7a)

2/x=5/x-2

multiply both sides by x

x*2/x=x*5/x – x*2

2=5-2x

5-2x=2

-2×2-5

-2x=-3

x=-3/-2

x=3/2

7b)

vol=1/3*base*height

=1/3 * 1/2 * 8*5sin30* 14

=20/3 * 1/2 * 14

=46.67

=47cm^3(nearest whole number)

 

8a)

U={1,2,3,4…,20}

A={1,2,3,4,….,15}

B={2,4,6,….20}

C={2,3,5,7,11,13,17,19}

i)

AnBnC

{1,2,3,…15}n{2,4,6,…20)nC

{2,4,6,8,10,12,14}n{2,3,5,7,11,13,17,18}

={2}

ii)

A^c U (B-C)

{16,17,18,19,20}U{3,4,5,6,7,8,9,10,11,12,13,14,16,17,18,19}

{3,4,5,6,7,8,10,12,13,14,16,17,18,19,20}

8b)

i)Pr(T,3)=1/12

ii)Pr(H and odd no)=3/12

iii)Pr(H and prime no)=3/12 =1/4

 

9a)

A=1/2*bh

45= 1/2*bh

h= 45/1/2*b

h= 45/1/2*28

h=45/14

h=3.21m

While b=A/1/2*h

b= 45/1/2*3.21

b=45/1.60

b=28.12cm

9b)

Area of a circle is given 68 whole no 4/7cm^2

i. Diameter =A/2=616/2 =308

ii. Circum = Πr^2

=22/7*308^2

=3.14*94864

=297872.9

=2.9*10^6

 

14a)

rentable value=N10,000,000

annual rates=75k*10,000,000

=750,000,000

=N7,500,000

14b)

P=N420,000, R=7 1/2%, n=3yrs

A=P(1+ R/100)^n

=420,000(1+0.075)^3

=420,000(1.075)

=N521,764.69k

C.I=A-P

=521,764.69-420,000

=N101,764.69

++++++++++++++++++++++++++++++

I PITY THOSE THAT COPY

WRONG ANSWERS FROM OTHER SITES. USE OURS IF U WERE DIRECTED HERE WE
CONFIRM B4 DISTRIBUTION.